要从数据库中获取数据并在下拉框中显示,可以按照以下步骤进行操作:
$servername = "数据库服务器地址";
$username = "用户名";
$password = "密码";
$dbname = "数据库名";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("连接失败: " . $conn->connect_error);
}
$sql = "SELECT id, name FROM table_name";
$result = $conn->query($sql);
echo "<select>";
while($row = $result->fetch_assoc()) {
echo "<option value='" . $row["id"] . "'>" . $row["name"] . "</option>";
}
echo "</select>";
$conn->close();
完整的代码示例:
$servername = "数据库服务器地址";
$username = "用户名";
$password = "密码";
$dbname = "数据库名";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("连接失败: " . $conn->connect_error);
}
$sql = "SELECT id, name FROM table_name";
$result = $conn->query($sql);
echo "<select>";
while($row = $result->fetch_assoc()) {
echo "<option value='" . $row["id"] . "'>" . $row["name"] . "</option>";
}
echo "</select>";
$conn->close();
请注意替换代码中的数据库服务器地址、用户名、密码、数据库名和表名等相关信息。
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